Текущий sql: SELECT
clientId,
groupID,
COUNT(DISTINCT clientId) AS visitors,
ROUND(AVG(price),2) AS price
FROM
(
SELECT 'devices'.*, MAX('url'.price) AS price
FROM 'devices', 'url'
WHERE 'devices'.visited_url = 'url'.website
) devices
GROUP BY 'devices'.groupID
В ...
10 апр. 2018, в 06:47