LinkedListNode в Java

Я пытаюсь преобразовать код С# в Java. Я почти переделал все, кроме трех строк в if.

код С#

LinkedList<T> buk = new LinkedList();
LinkedListNode<T> current = buk.First;
LinkedListNode<T> previous = null;
if (fooCondition) {
    previous = current.Previous;
} else {
    previous = current;
    current = current.Next;
}

Эквивалентный код Java

LinkedList<T> buk = new LinkedList<>();
T current = buckets.getFirst();
T previous = null;
if (fooCondition) {
    ?                   //previous = current.Previous;  
} else {
    ?                   //previous = current;
    ?                   //current = current.Next;
}

Поскольку в Java нет класса LinkedListNode, может ли кто-нибудь предположить, что будет эквивалентным кодом в Java?

РЕДАКТИРОВАТЬ

Кажется, что полный код очень важен для получения помощи. Вот функция С# из ссылки

  protected void MergeBuckets()
    {
        LinkedListNode<Bucket> current = buckets.First;
        LinkedListNode<Bucket> previous = null;

        int k = (int)Math.Ceiling(1 / epsilon);             // k=1/eps as integer
        int kDiv2Add2 = (int)(Math.Ceiling(0.5 * k) + 2);   // k/2 as integer
        // at this point 1/k <= eps, k >= 2, hence requires eps >= 0.5

        // number of concecutive buckets with same count causing a 
        // merge of the oldest two of those buckets
        int numberOfSameCount = 0;

        // traverse buckets from first to last, hence in order of 
        // descending timestamp and ascending count
        while (current != null)
        {
            // previous and current bucket have same count, increment counter
            if (previous != null && previous.Value.Count == current.Value.Count)
                numberOfSameCount++;
            // current is first with that count, reset counter to 1
            else
                numberOfSameCount = 1;

            // detect need for a merge
            if (numberOfSameCount == kDiv2Add2)
            {
                // merge buckets into current and remove previous
                current.Value.Timestamp = previous.Value.Timestamp;                 // take most recent timestamp
                current.Value.Count = previous.Value.Count + current.Value.Count;   // sum the counts of the buckets, 
                                                                                    // i.e. next power of two

                buckets.Remove(previous);

                // note that a merged bucket might cause a cascade of merges due to its new count,
                // hence the new current node should point to the merged bucket otherwise the 
                // cascade might go unnoticed, temporarily violating the invariant!

                previous = current.Previous;    // merged bucket previous, since old previous is removed
                //current = current;            // trivial, merged bucket is new current

                // at this iteration, the traversal stays in place
            }
            // no merge required, continue normally
            else
            {
                previous = current;         // old current bucket or merged bucket
                current = current.Next;     // current or merged next

                // at this iteration, the traversal moves to the next (older) bucket
            }
        }
    }