У меня есть таблицы клиентов, кампаний, сделок и фактов2. Я написал такой запрос, как показано ниже, как
SELECT id,
(select customer.name from customer where customer.id = facts2.customer_id)
AS Customername,
(select campaign.name from campaign where campaign.id = facts2.campaign_id)
AS Campaignname,
(select deal.name from jb_deal where deal.id = facts2.deal_id)
AS Dealname,
revenue
from facts2;
+--------------+-------------+-------------------+----------+ | Customername | Campaignanme | Dealname | revenue | +-------------+-------------+-------------------------------+ | A | Camp1 | Deal1 | 100 | | A | Camp1 | Deal2 | 200 | | A | Camp2 | Deal3 | 300 | | B | CampB | DealB1 | 100 | | B | CampB | DealB2 | 200 | | C | CampC | Deal3 | 300 | +-------------+-------------+--------------------------------+
Я хочу отобразить таблицу sql без повторения имен клиентов и имен кампаний, как показано ниже.
+--------------+-------------+-------------------+----------+ | customername | campaignanme | dealname | Revenue | +-------------+-------------+-------------------------------+ | A | Camp1 | Deal1 | 100 | | | | Deal2 | 200 | | | Camp2 | Deal3 | 300 | | B | CampB | DealB1 | 100 | | | | DealB2 | 200 | | C | CampC | Deal3 | 300 | +-------------+-------------+--------------------------------+
Вы не сможете сделать это, тем не менее, вы можете использовать UNION для принятия различных записей. Если вы хотите, вы можете так выглядеть.
SELECT `result`.`Customername`,`result`.`Campaignname`,
GROUP_CONCAT(`result`.`Dealname`) AS `Dealname`,SUM(`revenue`) AS `revenue` FROM (SELECT id,
(select customer.name from customer where customer.id = facts2.customer_id)
AS Customername,
(select campaign.name from campaign where campaign.id = facts2.campaign_id)
AS Campaignname,
(select deal.name from jb_deal where deal.id = facts2.deal_id)
AS Dealname,
revenue
from facts2) AS `result` GROUP BY `result`.`Campaignname`,`result`.`Customername`;
результат будет таким, каким он выглядит
+--------------+-------------+-------------------+----------+
| Customername | Campaignanme | Dealname | revenue |
+-------------+-------------+-------------------------------+
| A | Camp1 | Deal1,Deal2 | 300 |
| A | Camp2 | Deal3 | 300 |
| B | CampB | DealB1,DealB2 | 300 |
| C | CampC | Deal3 | 300 |
+-------------+-------------+--------------------------------+
join = cartesian product
, вместо этого вы можете попробовать union