MySQL JSON_SEARCH - не работает с двойными кавычками

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MySQL JSON_SEARCH - не работает с двойными кавычками

0

У меня есть данные json, как указано в user_details:

"[{"value":"sachin","label":"What your "first" name?"},{"value":"[email protected]","label":"What your email?"},{"value":"+911234567890","label":"What your "phone" number?"},{"value":"xyz","label":"What your city?"},{"value":"abc","label":"What your address?"}]"

Для этого я попытался с нижеследующим запросом, но он дает ошибку. Ошибка происходит ТОЛЬКО, когда мои данные содержат двойные кавычки ("). Как я могу сделать эту работу?

SELECT CASE WHEN json_search(user_details, 'one', '%name%', null, '$[*].label')
IS NOT NULL THEN 'name'
WHEN json_search(user_details, 'one', '%email%', null, '$[*].label')
IS NOT NULL THEN 'email'
WHEN json_search(user_details, 'one', '%phone number%', null, '$[*].label') IS NOT NULL THEN 'phone'
ELSE 'id' END type,
CASE WHEN json_search(user_details, 'one', '%name%', null, '$[*].label')
IS NOT NULL THEN
json_unquote(json_extract(user_details, concat(json_unquote(replace(json_search(user_details, 'one', '%name%', null,
'$[*].label'),'.label', '')),'.value')))
WHEN json_search(user_details, 'one', '%email%', null, '$[*].label') IS NOT NULL THEN
json_unquote(json_extract(user_details, concat(json_unquote(replace(json_search(user_details, 'one', '%email%', null,
'$[*].label'),'.label', '')),'.value')))
WHEN json_search(user_details, 'one', '%phone number%', null, '$[*].label') IS NOT NULL THEN
json_unquote(json_extract(user_details,concat(json_unquote(replace(json_search(user_details, 'one', '%phone%', null,
'$[*].label'),'.label', '')),'.value')))ELSE user_id END value FROM json_user;

dang 12 дек. 2017, в 19:27

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Теги:

mysql

json

1 ответ

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wchiquito · Answer 1 · 2017-12-13T08-42-00.000Z

Пытаться:

mysql> SET @'user_details' := '[
    '>   {"value":"sachin","label":"What\ your \\"first\\" name?"},
    '>   {"value":"[email protected]","label":"What\ your email?"},
    '>   {"value":"+911234567890","label":"What\ your \\"phone\\" number?"},
    '>   {"value":"xyz","label":"What\ your city?"},
    '>   {"value":"abc","label":"What\ your address?"}
    '> ]';
Query OK, 0 rows affected (0.00 sec)

mysql> SELECT JSON_VALID(@'user_details');
+-----------------------------+
| JSON_VALID(@'user_details') |
+-----------------------------+
|                           1 |
+-----------------------------+
1 row in set (0.00 sec)

mysql> SELECT
    -> JSON_UNQUOTE(
    ->   JSON_EXTRACT(
    ->     @'user_details',
    ->     JSON_UNQUOTE(
    ->       REPLACE(
    ->         JSON_SEARCH(
    ->           @'user_details',
    ->           'one',
    ->           '%phone%',
    ->           null,
    ->           '$[*].label'
    ->         ),
    ->         '.label',
    ->         '.value'
    ->       )
    ->     )
    ->   )
    -> ) 'phone';
+---------------+
| phone         |
+---------------+
| +911234567890 |
+---------------+
1 row in set (0.00 sec)