Я работаю над таблицей Join с объединением 5 разных таблиц. Так как я написал код для объединения всех таблиц и отлично работает без таблицы соединений
как вы можете видеть код
SELECT sku,
sum(units_ordered) as units_ordered
FROM (
SELECT sku, units_ordered
FROM tbl_sku_units_order
UNION ALL
SELECT sku, units_ordered
FROM tbl_sku_units_order_de
UNION ALL
SELECT sku, units_ordered
FROM tbl_sku_units_order_es
UNION ALL
SELECT sku, units_ordered
FROM tbl_sku_units_order_fr
UNION ALL
SELECT sku, units_ordered
FROM tbl_sku_units_order_it
) AllMarketplace
group by sku
ORDER BY units_ordered DESC;
как вы можете видеть результат в первой ссылке на db fiddle
https://www.db-fiddle.com/f/nbGcxACaf4doHRssJDSyRN/0, и результат верен
Вы можете увидеть "H-Root-M012S-Black 87", что является правильной суммой акций QTY.
Мне нужно, чтобы они присоединились к одной из других таблиц в качестве левого соединения. Вот код в скрипте db
https://www.db-fiddle.com/f/dxqsU4enjRYqk7du7VEB4d/0
это код, который я написал
SELECT
ls.sku AS list_sku,
COALESCE(MIN(suo.sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(suo.units_ordered), 0) AS units_ordered
FROM
(SELECT
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order
UNION ALL
SELECT
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_de
UNION ALL
SELECT
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_es
UNION ALL
SELECT
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_fr
UNION ALL
SELECT
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_it
) as t1,
tbl_list_sku AS ls
LEFT JOIN
tbl_sku_units_order AS suo ON suo.sku = ls.sku
GROUP BY ls.sku
ORDER BY units_ordered DESC;
И он вернулся хорошо, но расчет неправильный
Я подозреваю, что это связано с проблемой группы? Я должен настроить его в группе, но все результаты возвращают одинаковые результаты вместе с правыми или внутренними таблицами объединения.
Ваш SQL должен выглядеть следующим образом:
SELECT
ls.sku AS list_sku,
COALESCE(MIN(suo.sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(suo.units_ordered), 0) AS units_ordered
FROM
(SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order
UNION ALL
SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_de
UNION ALL
SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_es
UNION ALL
SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_fr
UNION ALL
SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_it
) as t1 join
tbl_list_sku AS ls on t1.sku = ls.sku
LEFT JOIN
tbl_sku_units_order AS suo ON suo.sku = ls.sku
GROUP BY ls.sku
ORDER BY units_ordered DESC;
SELECT
ls.sku AS list_sku,
COALESCE(MIN(suo.sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(suo.units_ordered), 0) AS units_ordered
FROM tbl_list_sku AS ls left join
(SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order
UNION ALL
SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_de
UNION ALL
SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_es
UNION ALL
SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_fr
UNION ALL
SELECT sku,
COALESCE(MIN(sku), 'Not Sold') AS sold_sku,
COALESCE(SUM(units_ordered), 0) AS units_ordered
FROM tbl_sku_units_order_it
) as t1 on t1.sku = ls.sku
LEFT JOIN
tbl_sku_units_order AS suo ON suo.sku = ls.sku
GROUP BY ls.sku
ORDER BY units_ordered DESC;