Ресурс запроса не найден Ошибка 404 при запуске проекта Maven на Tomcat в Eclipse

Я запускаю приложение Spring-Rest на maven на tomcat в eclipse. При запуске проекта на сервере tomcat отображается 404 ресурса запроса не найден. Я импортировал оставшийся проект из (https://github.com/spring-projects/spring-data-book)

мой файл web.xml:

<?xml version="1.0" encoding="ISO-8859-1" standalone="no"?>
 <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">


<display-name>roo-spring-data-jpa</display-name>

<description>Roo generated roo-spring-data-jpa application</description>


<!-- Enable escaping of form submission contents -->
<context-param>
    <param-name>defaultHtmlEscape</param-name>
    <param-value>true</param-value>
</context-param>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath*:META-INF/spring/applicationContext*.xml</param-value>
</context-param>

<filter>
    <filter-name>CharacterEncodingFilter</filter-name>
    <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
    <init-param>
        <param-name>encoding</param-name>
        <param-value>UTF-8</param-value>
    </init-param>
    <init-param>
        <param-name>forceEncoding</param-name>
        <param-value>true</param-value>
    </init-param>
</filter>

<filter>
    <filter-name>HttpMethodFilter</filter-name>
    <filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
</filter>

<filter>
    <filter-name>Spring OpenEntityManagerInViewFilter</filter-name>
    <filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
</filter>
<filter-mapping>
    <filter-name>CharacterEncodingFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<filter-mapping>
    <filter-name>HttpMethodFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<filter-mapping>
    <filter-name>Spring OpenEntityManagerInViewFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<!-- Handles Spring requests -->
<servlet>
    <servlet-name>roo-spring-data-jpa</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>WEB-INF/spring/webmvc-config.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>roo-spring-data-jpa</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<session-config>
    <session-timeout>10</session-timeout>
</session-config>

<error-page>
    <exception-type>java.lang.Exception</exception-type>
    <location>/uncaughtException</location>
</error-page>

<error-page>
    <error-code>404</error-code>
    <location>/resourceNotFound</location>
</error-page>

мой файл ApplicationConfig.java

  package com.oreilly.springdata.rest;

  import javax.persistence.EntityManagerFactory;
  import javax.sql.DataSource;

 import org.springframework.context.annotation.Bean;
 import org.springframework.context.annotation.ComponentScan;
 import org.springframework.context.annotation.Configuration;
 import       org.springframework.data.jpa.repository.config.EnableJpaRepositories;
import org.springframework.jdbc.datasource.embedded.EmbeddedDatabaseBuilder;
 import org.springframework.jdbc.datasource.embedded.EmbeddedDatabaseType;
 import org.springframework.orm.jpa.JpaTransactionManager;
 import org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean;
  import org.springframework.orm.jpa.vendor.Database;
  import org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter;
  import org.springframework.transaction.PlatformTransactionManager;
  import org.springframework.transaction.annotation.EnableTransactionManagement;

  /**
  * Spring JavaConfig configuration class to setup a Spring container   and    infrastructure components like a
* {@link DataSource}, a {@link EntityManagerFactory} and a {@lin PlatformTransactionManager}.
* 
* @author Oliver Gierke
*/
 @Configuration
@ComponentScan
@EnableJpaRepositories
@EnableTransactionManagement
 class ApplicationConfig {

/**
 * Bootstraps an in-memory HSQL database.
     * 
 * @return
 * @see http 
 *      ://static.springsource.org/spring/docs/3.1.x/spring-framework-reference/html/jdbc.html#jdbc-embedded-database
 *      -support
 */
@Bean
public DataSource dataSource() {
    EmbeddedDatabaseBuilder builder = new EmbeddedDatabaseBuilder();
    return builder.setType(EmbeddedDatabaseType.HSQL).build();
}

/**
 * Sets up a {@link LocalContainerEntityManagerFactoryBean} to use Hibernate. Activates picking up entities from the
 * project base package.
 * 
 * @return
 */
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {

    HibernateJpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter();
    vendorAdapter.setDatabase(Database.HSQL);
    vendorAdapter.setGenerateDdl(true);

    LocalContainerEntityManagerFactoryBean factory = new LocalContainerEntityManagerFactoryBean();
    factory.setJpaVendorAdapter(vendorAdapter);
    factory.setPackagesToScan(getClass().getPackage().getName());
    factory.setDataSource(dataSource());

    return factory;
}

@Bean
public PlatformTransactionManager transactionManager() {

    JpaTransactionManager txManager = new JpaTransactionManager();
    txManager.setEntityManagerFactory(entityManagerFactory().getObject());
    return txManager;
}

}

Я был поражен здесь в течение часа, поэтому я размещаю его здесь. Кто-нибудь может мне помочь, пожалуйста. Заранее спасибо.